plz help me mama very urgent

[educon999]

Consider a magnetic disk drive with 8 surfaces, 512 tracks per surface, and 64 sectors per track. Sector size is 1 KB. The average seek time is 8 ms, the track- to- track access time is 1.5 ms, and the drive rotates at 3600 rpm. Successive tracks in a cylinder can be read without head movement. 
a. What is the disk capacity?
b. What is the average access time? Assume this file is stored in successive sectors and tracks
    of successive cylinders, starting at sector 0, track 0, of cylinder i.
c. Estimate the time required to transfer a 5- MB file.

Please can anyone of you answer this please i just have 2 hrs more to submit my assignment

[k2s]

*7*^ *7*^ *7*^ *7*^ oka line sadavaganey laksha doubts vasthunnai.......

[gerrard]

[quote author=k2s link=topic=169621.msg2056268#msg2056268 date=1300493483]
*7*^ *7*^ *7*^ *7*^ oka line sadavaganey laksha doubts vasthunnai.......
[/quote]

  @gr33d @gr33d @gr33d

[k2s]

[quote author=ChittiNaidu link=topic=169621.msg2056284#msg2056284 date=1300493667]
disk capacity = total num of sectors * 512 bytes per sector
           
sector perside = track per side* sectors per track = 512* 64

disk capacity = [8 surfaces ( 512*64) * 512] bytes
[/quote] sAng_banghead2 sAng_banghead2

[Gachibowli_Diwakar]

Computer Organization and Architecture: Designing for Performance By William Stallings .. aah subject lo assignment isthe aah question ni ikkada copy/paste chesesava mama  *7*^ *7*^ *7*^

[htnamus]

[quote author=ChittiNaidu link=topic=169621.msg2056284#msg2056284 date=1300493667]
disk capacity = total num of sectors * 512 bytes per sector
           
sector perside = track per side* sectors per track = 512* 64

disk capacity = [8 surfaces ( 512*64) * 512] bytes
[/quote]chitti  you rock you rock you rock you rock you rock you rock

[educon999]

avunu mama deeniki 30 marks anta mama plzzz help

[gerrard]

[quote author=Musugu_Veerudu link=topic=169621.msg2056293#msg2056293 date=1300493770]
Computer Organization and Architecture: Designing for Performance By William Stallings .. aah subject lo assignment isthe aah question ni ikkada copy/paste chesesava mama  *7*^ *7*^ *7*^
[/quote]

  LoL.1q LoL.1q LoL.1q LoL.1q LoL.1q LoL.1q LoL.1q LoL.1q

[gerrard]

[quote author=ChittiNaidu link=topic=169621.msg2056284#msg2056284 date=1300493667]
disk capacity = total num of sectors * 512 bytes per sector
           
sector perside = track per side* sectors per track = 512* 64

disk capacity = [8 surfaces ( 512*64) * 512] bytes
[/quote]


  you rock you rock you rock you rock you rock you rock you rock

[k2s]

[quote author=Musugu_Veerudu link=topic=169621.msg2056293#msg2056293 date=1300493770]
Computer Organization and Architecture: Designing for Performance By William Stallings .. aah subject lo assignment isthe aah question ni ikkada copy/paste chesesava mama  *7*^ *7*^ *7*^
[/quote]

i hate that subject....  sSc_hiding2 .. assalu ardam ee ayyedi kadu  sAng_banghead2

[educon999]

[quote author=ChittiNaidu link=topic=169621.msg2056284#msg2056284 date=1300493667]
disk capacity = total num of sectors * 512 bytes per sector
           
sector perside = track per side* sectors per track = 512* 64

disk capacity = [8 surfaces ( 512*64) * 512] bytes
[/quote]

Chitti inkonchem detailed gaaa answer post cheyyava please naaku eee subject knowledge nill

[k2s]

[quote author=educon999 link=topic=169621.msg2056335#msg2056335 date=1300494217]
Chitti inkonchem detailed gaaa answer post cheyyava please naaku eee subject knowledge nill
[/quote]

antha clear seppadu kada ....... formulas kuda ichadu........ ICSE aa ??? leks CBSE aa ????

[educon999]

[quote author=k2s link=topic=169621.msg2056344#msg2056344 date=1300494304]
antha clear seppadu kada ....... formulas kuda ichadu........ ICSE aa ??? leks CBSE aa ????
[/quote]


Mama eppudu naa knowledge ni nuvvu test cheyyodhu inka time 1.30 vundhiiii.nuvvu konchem sepu cool avvu boss *7*^ *7*^ *7*^ *7*^ *7*^

[educon999]

[quote author=ChittiNaidu link=topic=169621.msg2056365#msg2056365 date=1300494516]
Total storage capacity of a hard drive = Total Number of Sectors * 512 bytes per sector

neeku 8 surfaces (sides) unnai....total sectors calc cheyali ante....

Total Number of Sectors = Sectors Per Side * Number of Heads  ( u have 512 sector per track and 64 heads) so total into 8  idi first part of 1st formula...
[/quote]

Thanks chitti so migatha 2 partss kuda post cheyyi mama

[k2s]

[quote author=ChittiNaidu link=topic=169621.msg2056372#msg2056372 date=1300494638]
neeku edi em paert ani clear ga telvali ante..see this video..

[url=http://www.youtube.com/watch?v=LDEryoHK39o#]Calculating access time for a hard drive[/url]
[/quote]
[quote author=ChittiNaidu link=topic=169621.msg2056375#msg2056375 date=1300494694]
Access time avanni calculate cheyali ante..u need to know some stuff...

nenu cheyagalanu..but time kavlai right now im in office....apapti varaku ivi chudu u will get an idea..

The access time of a disk is the time taken to retrieve the data. This access time is made up primarily of two factors, one factor is the rotational latency and the other is the seek time. Rotational latency is the time taken for the desired sector to pass under the recording head. SATA disks typically spin at a rotational speed of 7200 R.P.M. so this means that it will take 1/60th of a second to make one revolution (1/60th of a second is equal to 8.3 milliseconds). When calculating the rotational delay we calculate the average delay, which is the time taken to perform one half of a disk revolution = 4.17 milliseconds.

The seek time is the time taken to move the heads to the desired track and this tends to vary from drive to drive but an average seek time of 10 milliseconds is not uncommon. When we add the rotational latency and the seek time together we get the access time. In this example, the access time would be quoted as 14 milliseconds. The time taken to actually transfer the data is known as the data transfer rate, but as this is normally very fast compared to the latency and seek times, we can usually ignore it. Modern disk drives have rotational speeds of up to 15,000 R.P.M., which result in very fast access times.

Source kavalante idigo.... [url=http://www.brighthub.com/computing/windows-platform/articles/7362.aspx#ixzz1H07U6vCP]http://www.brighthub.com/computing/windows-platform/articles/7362.aspx#ixzz1H07U6vCP[/url]
[/quote]


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