Maths Geometry Problem.

[Rao_Garu]

An electric wire 40 meters is made into two pieces. 1st part of the wire is used to form a circle with radius r, and the other part of the wire is used to form a square. What is the total area, in square meters, of the circular and the square regions in terms of r?

[Spartan]

Circle...dani perimeter = 2*pi*r = 20mts (considereing the wire was split into two equal parts)

so r = 70/22

Square = dani perimeter 20meters anukunte... 4 (a=side of square) = 20 implies a= 5mts

area of square = 25sqmts..

inka r ki 25 ki relation veskovali....

pi r square + a square area vesko answer vastai...

[Jatka Bandi]

[(40-2πr)[sup]2[/sup]+(16πr[sup]2[/sup])]/16
=
[1600-160r+r[sup]2[/sup](16π-4π[sup]2[/sup])]/16

[Rao_Garu]

[quote name='ChittiNaidu' timestamp='1340300234' post='1302004779']
Circle...dani perimeter = 2*pi*r = 20mts ([size=6]considereing the wire was split into two equal parts[/size])

so r = 70/22

Square = dani perimeter 20meters anukunte... 4 (a=side of square) = 20 implies a= 5mts

area of square = 25sqmts..

inka r ki 25 ki relation veskovali....

pi r square + a square area vesko answer vastai...
[/quote]
No considerations pls....your answer partially correct ...I want answer interms of r.

[Jatka Bandi]

circle area 2πr=x anukundam... appudu square ki use chese wire length 40-x......... so one side of square would be (40-x)/4 total area of square and circle is [(40-x)/4][sup]2[/sup] + πr[sup]2[/sup]

Substitute x=2πr

[150bryant]

assume length of the wire 2L...
two halves antey L for square and L for wire..

circular perimeter = 2 pi r which equals L
perimeter of square = L
square has 4 sides..therefore. one side = L/4
side of square = L/4 = (2pi r)/ 4 = (pi r /2)
area of square =( pi * r * pi * r )/4 area of circle = Pi* r * r

[Rao_Garu]

[quote name='bantrothu bullabbai' timestamp='1340300489' post='1302004811']
[(40-2πr)[sup]2[/sup]+(16πr[sup]2[/sup])]/16
=
[1600-160r+r[sup]2[/sup](16π-4π[sup]2[/sup])]/16
[/quote]
mastaru...ans adi kaadu

[Jatka Bandi]

[quote name='ChittiNaidu' timestamp='1340300234' post='1302004779']
Circle...dani perimeter = 2*pi*r = 20mts (considereing the wire was split into two equal parts)

so r = 70/22

Square = dani perimeter 20meters anukunte... 4 (a=side of square) = 20 implies a= 5mts

area of square = 25sqmts..

inka r ki 25 ki relation veskovali....

pi r square + a square area vesko answer vastai...
[/quote]nuvvendi AIDS vachinodi lekka aa display pic....

[k2s]

abbooo ikkada doctors saana mandi unnaru kada

[Rao_Garu]

[quote name='bantrothu bullabbai' timestamp='1340300754' post='1302004835']
circle area 2πr=x anukundam... appudu square ki use chese wire length 40-x......... so one side of square would be (40-x)/4 total area of square and circle is [(40-x)/4][sup]2[/sup] + πr[sup]2[/sup]
[/quote]
Bulls eye....correct

[150bryant]

pi*r^2 ((pi*r /4) +1)

[Jatka Bandi]

[quote name='Rao_Garu' timestamp='1340300881' post='1302004857']
Bulls eye....correct
[/quote]
[quote name='Rao_Garu' timestamp='1340300781' post='1302004842']
mastaru...ans adi kaadu
[/quote]danni simplify cheste paina ichindi vastundi.... wrong answer annav.... [img]http://www.andhrafriends.com/uploads/profile/photo-thumb-11780.jpg?_r=0[/img]

[Calm Guy]

(40-r)^2/16 + Pi*r^2

[Jatka Bandi]

[quote name='Calm Guy' timestamp='1340301043' post='1302004867']
(40-r)^2/16 + Pi*r^2
[/quote]
40-r kadu 40-2pi r

[pinky123]

[quote name='bantrothu bullabbai' timestamp='1340300754' post='1302004835']
circle area 2πr=x anukundam... appudu square ki use chese wire length 40-x......... so one side of square would be (40-x)/4 total area of square and circle is [(40-x)/4][sup]2[/sup] + πr[sup]2[/sup]

Substitute x=2πr
[/quote]

[img]http://i361.photobucket.com/albums/oo54/Imdareaper/Emoticons/Whistle.gif[/img]