Math Question... Is It Possible?

[cavaliers]

Guys,

I have the coordinates X and Y. Is there a way we can find t?



Thanks.

[img]http://i48.tinypic.com/6nuohi.jpg[/img]

[chittimallu5]

x and y values cheppu

[cavaliers]

X and Y coordinates Arbitrary bhayya....

Sensor a point meeda padinappudu.. aa values vastaay...

We can assume (70, 5) for now.


May ne t in terms of X and Y cheyochu emo kada....

[chittimallu5]

too many unknowns to get t in yerms of x and y.....wat do u say?

[punyavathi]

2 pegs vesukoni padukokaa, ee x and y manaki enuduku bhayyaa

[chittimallu5]

y in terms of t rayali first .....for that u need hypotenuse which is unknown too

[cavaliers]

actually edo untundhi kada formula....

X/Square root (X2 + Y2) = t/ Square roon(t2 + Y2)

but.. daaniki evo conditions untaaya ani kuda doubt undhi... taking angles into consideration

[chittimallu5]

[quote name='cavaliers' timestamp='1352736623' post='1302783194']
actually edo untundhi kada formula....

X/Square root (X2 + Y2) = t/ Square roon(t2 + Y2)

but.. daaniki evo conditions untaaya ani kuda doubt undhi... taking angles into consideration
[/quote]angle ledhu hypotenuse ledhu....naa burra ki aithe em thattatle.....unknows are too many anipisthundhi naku

[cavaliers]

[quote name='punyavathi' timestamp='1352736520' post='1302783175']
2 pegs vesukoni padukokaa, ee x and y manaki enuduku bhayyaa
[/quote]


leechaka Manager adugutaadeemo ani.....

inka maa office lo mandu supply cheyadam leedu bhayya...

[paampachak]

nee ayya t x ni ye ratio lo divide sestundo telikunta etta septam vay

[powerstar02]

Point 1: First thing X and Y arbitrary aythe you must specify condition X>T .

Point 2: maths properties vunay Similarities of traingles ani Angle side angle,AAA,SAS avi..apply cheyi....

similarity of trainlgles apply chesthe you can get the ratio of both hypotenuse kaani mundu avi satisfy chestado ledho check cheyi.. and then the equation/realation between them.....

[PRESIDENT_MUSTODU]

[quote name='chittimallu5' timestamp='1352736530' post='1302783177']
y in terms of t rayali first .....for that u need hypotenuse which is unknown too
[/quote]

[img]http://www.desigifs.com/sites/default/files/sunil1.gif?1290056327[/img]

[paampachak]

t/x = sqrt(t2 + y2)/ sqrt(x2 + y2)

[Jatka Bandi]

can u post link of image. thanks.

[cavaliers]

aa pedda triangle ki angle find cheseyochu bhayya

Tan (angle) = (y/x) kada

Right angled triangle kada --- inko angle 180- Inverse Tan( Y/X) vastundhi


kaani aa small triangle ki angle find cheyadam kashtam ... it has an unknown t.

I am not sure if its possible.. kaani asalu ee approach workout avutundha ani kuda thinking...!