nenusuper Posted November 12, 2012 Report Posted November 12, 2012 [quote name='cavaliers' timestamp='1352736623' post='1302783194'] actually edo untundhi kada formula.... X/Square root (X2 + Y2) = t/ Square roon(t2 + Y2) but.. daaniki evo conditions untaaya ani kuda doubt undhi... taking angles into consideration [/quote] ya dis formula is crct and i dont think angles need to be taken into consideration
cavaliers Posted November 12, 2012 Author Report Posted November 12, 2012 [quote name='paampachak' timestamp='1352736890' post='1302783235'] t/x = sqrt(t2 + y2)/ sqrt(x2 + y2) [/quote] Idhi workout avutundha? ee Formula? Do we need to have any condition?
nani8055 Posted November 12, 2012 Report Posted November 12, 2012 [quote name='cavaliers' timestamp='1352736623' post='1302783194'] actually edo untundhi kada formula.... X/Square root (X2 + Y2) = t/ Square roon(t2 + Y2) but.. daaniki evo conditions untaaya ani kuda doubt undhi... taking angles into consideration [/quote] idhi correct anukuntaa ... please advice
k2s Posted November 12, 2012 Report Posted November 12, 2012 [quote name='powerstar02' timestamp='1352736829' post='1302783227'] Point 1: First thing X and Y arbitrary aythe you must specify condition X>T . Point 2: maths properties vunay Similarities of traingles ani Angle side angle,AAA,SAS avi..apply cheyi.... similarity of trainlgles apply chesthe you can get the ratio of noth hypotenuse and hence the equation/realation between them..... [/quote]agreed X / Y = t / Y
powerstar02 Posted November 12, 2012 Report Posted November 12, 2012 [quote name='cavaliers' timestamp='1352736623' post='1302783194'] actually edo untundhi kada formula.... X/Square root (X2 + Y2) = t/ Square roon(t2 + Y2) but.. daaniki evo conditions untaaya ani kuda doubt undhi... taking angles into consideration [/quote] ya aa conditions ne SIMILARITY of TRIANGLES antaru....
nenusuper Posted November 12, 2012 Report Posted November 12, 2012 [quote name='cavaliers' timestamp='1352737043' post='1302783251'] Idhi workout avutundha? ee Formula? Do we need to have any condition? [/quote] [quote name='k2s' timestamp='1352737060' post='1302783254'] agreed X / Y = t / Y [/quote] both r crct , naku thelisi no conditions
nani8055 Posted November 12, 2012 Report Posted November 12, 2012 [quote name='cavaliers' timestamp='1352737043' post='1302783251'] Idhi workout avutundha? ee Formula? Do we need to have any condition? [/quote] conditions 90 degress okati common, ah " y" common..... inko side x and t looks similar... so SAS tho ah formula correct
cavaliers Posted November 12, 2012 Author Report Posted November 12, 2012 ala aithe for example, (70,5) anukundaam X and Y coordinates 70/Square root ( 70^2 _+ 5^2_) = t/ Square Root ( t^2 + 5^2) 70/ Square Root ( 4925) = t/ Square Root ( t^2 + 5^2) 4900/4925 = t^2/(t^2 + 25) -- Squaring both sides 4925/4900 = 1 + 25/t^2 (Inverting both sides and dividing) 25/4900 = 25/t^2 t = 70 ani vastundhi akda ala aithe.. even though if we have X > t?? Was I doing something wrong?
Ara_Tenkai Posted November 12, 2012 Report Posted November 12, 2012 [quote name='k2s' timestamp='1352737060' post='1302783254'] agreed X / Y = t / Y [/quote] Atla etla avuthadi bhaya... Here he is saying t is a part of X kada... I guess we can solve wid pythogerous theorem: ((X-t)+t)2 + Y2 = (Sqrt of x2+ y2)2
nani8055 Posted November 12, 2012 Report Posted November 12, 2012 [quote name='cavaliers' timestamp='1352737553' post='1302783315'] ala aithe for example, (70,5) anukundaam X and Y coordinated 70/Square root ( 70^2 _+ 5^2_) = t/ Square Root ( t^2 + 5^2) 70/ Square Root ( 4925) = t/ Square Root ( t^2 + 5^2) 4900/4925 = t^2/(t^2 + 25) 4925/4900 = 1 + 25/t^2 25/4900 = 25/t^2 t = 70 ani vastundhi akda ala aithe.. even though if we have X > t?? Was I doing something wrong? [/quote] t=+ or - 70 kadha...... so t = -70
girishv Posted November 12, 2012 Report Posted November 12, 2012 [quote name='Ara_Tenkai' timestamp='1352737680' post='1302783331'] Atla etla avuthadi bhaya... Here he is saying t is a part of X kada... I guess we can solve wid pythogerous theorem: ((X-t)+t)2 + Y2 = (Sqrt of x2+ y2)2 [/quote] e equation ni solve chesthe, x=x ani vasthundi....can't find t from this equation 1
cavaliers Posted November 12, 2012 Author Report Posted November 12, 2012 [quote name='nani8055' timestamp='1352737703' post='1302783335'] t=+ or - 70 kadha...... so t = -70 [/quote] Adenti Bhayya...t is a part of X kada....ala mari -70 ante... [quote name='Ara_Tenkai' timestamp='1352737680' post='1302783331'] Atla etla avuthadi bhaya... Here he is saying t is a part of X kada... I guess we can solve wid pythogerous theorem: ((X-t)+t)2 + Y2 = (Sqrt of x2+ y2)2 [/quote] Deeni konchem expand chesthe... (X-t)^2 _+t^2 +2 (X-t) t + Y^2 = (Sqrt of x2+ y2)2 X^2 _+ t^2 -2Xt + t^2 + 2Xt - 2t^2 + y^2 = (Sqrt of x2+ y2)2 X^2 _+ Y^2 = (Sqrt of x2+ y2)2 t asalu akada discard aipotundhi kada....
Kakateyudu Posted November 12, 2012 Report Posted November 12, 2012 [quote name='chittimallu5' timestamp='1352736530' post='1302783177'] [b]y in terms of t rayali first ..[/b]...for that u need hypotenuse which is unknown too [/quote] u can akkada 90 degrees kada angle 3 sides values vunnai in terms of t and y.
paampachak Posted November 12, 2012 Report Posted November 12, 2012 [quote name='cavaliers' timestamp='1352737043' post='1302783251'] Idhi workout avutundha? ee Formula? Do we need to have any condition? [/quote] Similar triangles condition cheppa I .. yaa these are not similar. Aa chinna triangle ni kindaki tippitho right angle triangle aithe (t2 + y2)2 + (x2 + y2)2 = (x + t)2
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