ChampakDas Posted November 13, 2012 Report Posted November 13, 2012 I said that when you consider it as separate triangles with the y as heights which would give x=t which doesnt make any sense thats what I was trying to tell..you chose y(small triangle) side as the base and then applied the similar triangle..thats the trick.. [quote name='jamajacha' timestamp='1352784962' post='1302788373'] thanks sleeping now..good night if only x=t is the answer...there is point in solving this problem.. by observation of problem itself..... u can say [/quote]
LOGON Posted November 13, 2012 Report Posted November 13, 2012 t can be any value on x, t is arbitrary and value of t can be found.. if the angle is known..
PMREDDY19 Posted November 13, 2012 Report Posted November 13, 2012 x= 3 . y = 2 t =1 kaniti ssooputho calculate sesa nia seppu.. evadina el ani adigithey ..
MAN UTD Posted November 13, 2012 Report Posted November 13, 2012 [quote name='cavaliers' timestamp='1352736066' post='1302783125'] Guys, I have the coordinates X and Y. Is there a way we can find t? Thanks. [img]http://i48.tinypic.com/6nuohi.jpg[/img] [/quote] bhayya without another variable, i think its not possible to find the value of t. another variable may be the angle of another side in the triangle with side 't'. (!(<
bhargava_v Posted November 13, 2012 Report Posted November 13, 2012 [quote name='Aamphat' timestamp='1352815630' post='1302788844'] Inthaki correct answer enti? [/quote] bhayya na email
cavaliers Posted November 13, 2012 Author Report Posted November 13, 2012 [quote name='jamajacha' timestamp='1352780493' post='1302788117'] [img]http://i47.tinypic.com/mkyu6w.jpg[/img] [/quote] [img]http://i48.tinypic.com/8x7eko.jpg[/img] Thanks Bhayya,.... I guess I found I was looking for.. actually I have to find out where did the sensor hit on that object of 5 Mts... Looking at your images.. I thought Instead of looking from the start of the object I can also look from the end of the object. so, the new t = (Y^2)/X solves the problem Thanks again....
vikuba Posted November 13, 2012 Report Posted November 13, 2012 [quote name='cavaliers' timestamp='1352822291' post='1302789303'] [img]http://i48.tinypic.com/8x7eko.jpg[/img] Thanks Bhayya,.... I guess I found I was looking for.. actually I have to find out where did the sensor hit on that object of 5 Mts... Looking at your images.. I thought Instead of looking from the start of the object I can also look from the end of the object. so, the new t = (Y^2)/X solves the problem Thanks again.... [/quote] two traingles similar ga unaayyee antey chaalu...u can solve for any variable available.. the concept of trigonometry and properties of triangles has been developed the similar triangles concept
vikuba Posted November 13, 2012 Report Posted November 13, 2012 [quote name='CASANOVA' timestamp='1352821984' post='1302789277'] bhayya na email [/quote] ratri ki sending
bhargava_v Posted November 13, 2012 Report Posted November 13, 2012 [quote name='Aamphat' timestamp='1352829248' post='1302790035'] ratri ki sending [/quote] will wait
bhargava_v Posted November 13, 2012 Report Posted November 13, 2012 [quote name='cavaliers' timestamp='1352822291' post='1302789303'] [img]http://i48.tinypic.com/8x7eko.jpg[/img] Thanks Bhayya,.... I guess I found I was looking for.. actually I have to find out where did the sensor hit on that object of 5 Mts... Looking at your images.. I thought Instead of looking from the start of the object I can also look from the end of the object. so, the new t = (Y^2)/X solves the problem Thanks again.... [/quote] idhi endi sudden ga bomma marindi..nee thesis title change chesava endi?
cavaliers Posted November 13, 2012 Author Report Posted November 13, 2012 [quote name='CASANOVA' timestamp='1352831571' post='1302790255'] idhi endi sudden ga bomma marindi..nee thesis title change chesava endi? [/quote] Leedu bhayya.... Looking at the same image in a different prospective anthe...
LOGON Posted November 13, 2012 Report Posted November 13, 2012 [quote name='LOGON' timestamp='1352786430' post='1302788441'] t can be any value on x, t is arbitrary and value of t can be found.. if the angle is known.. [/quote] [quote name='MAN UTD' timestamp='1352821728' post='1302789257'] bhayya without another variable, i think its not possible to find the value of t. another variable may be the angle of another side in the triangle with side 't'. (!(< [/quote] Agreed...
LOGON Posted November 13, 2012 Report Posted November 13, 2012 [quote name='cavaliers' timestamp='1352822291' post='1302789303'] [img]http://i48.tinypic.com/8x7eko.jpg[/img] Thanks Bhayya,.... I guess I found I was looking for.. actually I have to find out where did the sensor hit on that object of 5 Mts... Looking at your images.. I thought Instead of looking from the start of the object I can also look from the end of the object. so, the new t = (Y^2)/X solves the problem Thanks again.... [/quote] avi similar triangles etla ainayi dude.. avi similar triangles kaadu...
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