Time n distance

[aakathaai]

2 minutes ago, AlaElaAlaEla said:

utter gaadu raanu ani cheppadu 

aadni drawer pattukuni eedchukuni raa 

[AlaElaAlaEla]

2 minutes ago, aakathaai said:

aadni drawer pattukuni eedchukuni raa 

annai weekend mandu brand enti 

nallaberry ba tho epudanna vesava sitting

[aakathaai]

4 minutes ago, AlaElaAlaEla said:

annai weekend mandu brand enti 

nallaberry ba tho epudanna vesava sitting

Ninna just  smrinoff  anthe

Nallaberry ba tho 3 times esaa sitting

[Bahu]

40 minutes ago, AlaElaAlaEla said:

utter gaadu raanu ani cheppadu 

coming to sidhu liquor ? 

[reality]

On 10/6/2018 at 7:50 AM, Staysafebro said:

Bcom lo physics chadivava?

Lol

[Staysafebro]

22 hours ago, Heroin said:

Boats n streams

Relative Speed of two bodies moving towards each other s(1)+s(2) and in the same direction s(1)-s(2).

Boats, Streams and Escalators

If a constant distance is covered at speeds which are in an AP, then the times taken will be in an HP  and vice-versa (For eg, Upstream, Boat-speed, Downstream speeds will always be in AP. Same can be applied in escalator questions as well).

Speed(Upstream) = S(Boat)-S(River)

Speed(Downstream) = S(Boat)+S(River)

Speed(Boat) = [S(Downstream)+S(Upstream)]/2

Speed(River) = [S(Downstream)-S(Upstream)]/2

 

Motion of two bodies in a straight line

Two bodies start from opposite ends P & Q at the same time and move towards each other with speeds S(1) & S(2). After meeting each other, they take times of T(1) & T(2) to reach their destinations.

Time taken for them to meet sqrt[T(1)*T(2)]

S(1)/S(2) = sqrt[T(2)/T(1)]

Two bodies start from opposite ends P & Q at the same time and move towards each other with speeds S(1) & S(2). They reach the opposite ends and reverse directions. {S(1)>S(2) and S(1)

Total distance covered till nth meeting (2n-1)D and time taken (2n-1)D/S(1)+S(2).

Circular Motion

Number of distinct points: In same direction, a-b and in opposite direction a+b (Here a/b is the reduced ratio of speeds).

I hope that with this set of formulae, you will be able to solve TSD questions with ease.

I will be conducting a workshop on TSD where I will be discussing this and other concepts.

[Mitron]

19 hours ago, Amy99 said:

Not k 

😑

[Desi_guy]

12 hours ago, Amy99 said:

Ah mahanubhavudi ni dp laaga kuda pettukuntara ..

[Heroin]

12 hours ago, Staysafebro said:

Relative Speed of two bodies moving towards each other s(1)+s(2) and in the same direction s(1)-s(2).

Boats, Streams and Escalators

If a constant distance is covered at speeds which are in an AP, then the times taken will be in an HP  and vice-versa (For eg, Upstream, Boat-speed, Downstream speeds will always be in AP. Same can be applied in escalator questions as well).

Speed(Upstream) = S(Boat)-S(River)

Speed(Downstream) = S(Boat)+S(River)

Speed(Boat) = [S(Downstream)+S(Upstream)]/2

Speed(River) = [S(Downstream)-S(Upstream)]/2

 

Motion of two bodies in a straight line

Two bodies start from opposite ends P & Q at the same time and move towards each other with speeds S(1) & S(2). After meeting each other, they take times of T(1) & T(2) to reach their destinations.

Time taken for them to meet sqrt[T(1)*T(2)]

S(1)/S(2) = sqrt[T(2)/T(1)]

Two bodies start from opposite ends P & Q at the same time and move towards each other with speeds S(1) & S(2). They reach the opposite ends and reverse directions. {S(1)>S(2) and S(1)

Total distance covered till nth meeting (2n-1)D and time taken (2n-1)D/S(1)+S(2).

Circular Motion

Number of distinct points: In same direction, a-b and in opposite direction a+b (Here a/b is the reduced ratio of speeds).

I hope that with this set of formulae, you will be able to solve TSD questions with ease.

I will be conducting a workshop on TSD where I will be discussing this and other concepts.

Thanks