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Posted

Whenever I type this URL(http://192.168.1.75/cm?cmnd=increasevolume" ) and hit enter on a web browser, some action happens to my music system. But it's hard to enter URL every time.

So I tried to creating a button in HTML(see below). But when I click the button obviously it takes to that URL. I want the action to happen but stay on the same page. How to do?? TIA.

<button onclick="window.location.href='http://192.168.1.75/cm?cmnd=increasevolume''">Continue</button>

Posted
6 minutes ago, hotmaddy said:

Whenever I type this URL(http://192.168.1.75/cm?cmnd=increasevolume" ) and hit enter on a web browser, some action happens to my music system. But it's hard to enter URL every time.

So I tried to creating a button in HTML(see below). But when I click the button obviously it takes to that URL. I want the action to happen but stay on the same page. How to do?? TIA.

<button onclick="window.location.href='http://192.168.1.75/cm?cmnd=increasevolume''">Continue</button>

Target=# pettali, javascript rasi ajax call cheyochu

Posted
20 minutes ago, hotmaddy said:

Whenever I type this URL(http://192.168.1.75/cm?cmnd=increasevolume" ) and hit enter on a web browser, some action happens to my music system. But it's hard to enter URL every time.

So I tried to creating a button in HTML(see below). But when I click the button obviously it takes to that URL. I want the action to happen but stay on the same page. How to do?? TIA.

<button onclick="window.location.href='http://192.168.1.75/cm?cmnd=increasevolume''">Continue</button>

why you need browser ..it's just a GET request.. so use curl

curl <ur> .. html might be overkill... but you need to send an ajax request.. 

Posted
Just now, Mitron said:

manodu wmrt e location?

filims spelling in thumbnail check

  • Haha 1
Posted

make an ajaxrequest when button is clicked.... U shouldn’t  open window on each click of button 

Posted
1 minute ago, rrc_2015 said:

make an ajaxrequest when button is clicked.... U shouldn’t  open window on each click of button 

Send a Request To a Server

To send a request to a server, we use the open() and send() methods of the XMLHttpRequest object:

xhttp.open("GET""url"true);
xhttp.send();
Posted
2 hours ago, Spartan said:

 

Baa. Thanks.

 

Posted
2 hours ago, Paidithalli said:

Button ki href pedithe saripothadhi kadha 

href pedithe. A url unna page open avuthundi. I don't want that page to open but I want the action to happen.

Posted
2 hours ago, karthikn said:

why you need browser ..it's just a GET request.. so use curl

curl <ur> .. html might be overkill... but you need to send an ajax request.. 

I will google. for curl. Thanks.

Posted
2 hours ago, Katara said:

Target=# pettali, javascript rasi ajax call cheyochu

Will do more research. I don't know what ajax is.

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