Jatka Bandi Posted December 7, 2021 Report Posted December 7, 2021 i have varying string lengths in a column. I want all cells to have fixed length.. so if some cells have fewer characters, i want trailing spaces so that each cell makes up that fixed length.. how? for example, cells may look like dg aknb 2 gshjhj i want them to look like a fixed length of 6. so cells should end up looking like dg aknb 2 gshjhj first, second third cells lo characters taravata space include ayyindi choodandi.. so that all cells are 6 characters.. Quote
dasari4kntr Posted December 7, 2021 Report Posted December 7, 2021 Try padding functions… “Dasari”&REPT(“*”,3)) Dasari*** Quote
Jatka Bandi Posted December 7, 2021 Author Report Posted December 7, 2021 25 minutes ago, dasari4kntr said: Try padding functions… “Dasari”&REPT(“*”,3)) Dasari*** * badalu white space pedithey teesukotledu. White space ni character laaga define cheyyali.. adi avvatledu.. also, nee suggestion lo Dasari word ee variable length vuntey * kooda adapt avvali.. so that overall charcaters are 15.. ela chestaaru? Quote
dasari4kntr Posted December 7, 2021 Report Posted December 7, 2021 2 minutes ago, Jatka Bandi said: * badalu white space pedithey teesukotledu. White space ni character laaga define cheyyali.. adi avvatledu.. also, nee suggestion lo Dasari word ee variable length vuntey * kooda adapt avvali.. so that overall charcaters are 15.. ela chestaaru? Len(“dasari”) gives length of your name… adjust your cell formatter…and also… once you done with space…export to cav and notice there is space is appearing or not… Quote
Jatka Bandi Posted December 7, 2021 Author Report Posted December 7, 2021 for example I tried this for 5 character length. but * badalu space pedithe accept cheyatledu. deeniki kooda script rayaala ippudu! =LEFT(A1&"*****",5) Quote
DummyVariable Posted December 7, 2021 Report Posted December 7, 2021 =IF(VALUE(LEN(E2))=1,E2&" ",IF(VALUE(LEN(E2))=2,E2&" ",IF(VALUE(LEN(E2))=3,E2&" ",IF(VALUE(LEN(E2))=4,E2&" ",IF(VALUE(LEN(E2))=5,E2&" ",E2))))) 😆 Quote
DalchanChekka Posted December 7, 2021 Report Posted December 7, 2021 4 minutes ago, DummyVariable said: =IF(VALUE(LEN(E2))=1,E2&" ",IF(VALUE(LEN(E2))=2,E2&" ",IF(VALUE(LEN(E2))=3,E2&" ",IF(VALUE(LEN(E2))=4,E2&" ",IF(VALUE(LEN(E2))=5,E2&" ",E2))))) 😆 0 Quote
DummyVariable Posted December 7, 2021 Report Posted December 7, 2021 14 minutes ago, DalchanChekka said: 0 Put data in Cell E2 uncle Quote
Jatka Bandi Posted December 7, 2021 Author Report Posted December 7, 2021 20 minutes ago, DummyVariable said: =IF(VALUE(LEN(E2))=1,E2&" ",IF(VALUE(LEN(E2))=2,E2&" ",IF(VALUE(LEN(E2))=3,E2&" ",IF(VALUE(LEN(E2))=4,E2&" ",IF(VALUE(LEN(E2))=5,E2&" ",E2))))) 😆 then why smiley at the end? 1 Quote
DummyVariable Posted December 7, 2021 Report Posted December 7, 2021 2 minutes ago, Jatka Bandi said: then why smiley at the end? For fun uncle Quote
dasari4kntr Posted December 7, 2021 Report Posted December 7, 2021 48 minutes ago, Jatka Bandi said: for example I tried this for 5 character length. but * badalu space pedithe accept cheyatledu. deeniki kooda script rayaala ippudu! =LEFT(A1&"*****",5) Left function deniki? What if A1 is more than 5 characters…? Quote
Jatka Bandi Posted December 7, 2021 Author Report Posted December 7, 2021 5 minutes ago, dasari4kntr said: Left function deniki? What if A1 is more than 5 characters…? in my case, it can never be. Quote
DalchanChekka Posted December 7, 2021 Report Posted December 7, 2021 9 minutes ago, DummyVariable said: For fun uncle :S Quote
DummyVariable Posted December 7, 2021 Report Posted December 7, 2021 2 minutes ago, DalchanChekka said: :S 1 Quote
dasari4kntr Posted December 7, 2021 Report Posted December 7, 2021 1 minute ago, Jatka Bandi said: in my case, it can never be. Then it will work for you… space might not visible in excel until unless you custom format cell (try custom formatter ############) else export to csv and open in notepad and see spaces are there or not… Quote
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