Okkamogadu Posted July 8, 2011 Report Posted July 8, 2011 [quote author=mirchieee link=topic=210373.msg2573737#msg2573737 date=1310145373]weight ekkuva vunna danni matrame enduku teesukuntav babai ...neeku teliyadu kada defective coin hígherooo... lighterooo....incase adi lighter anuko..appudu takkuva weight vunna vatini kuda alage chusu kovali kada..ante mottam double avtundi...so 6 avtundi kada.... sCo_^Y sCo_^Y[/quote]yh 6 correste according to the question... nennu high weight ane fix aypoya indakati nunchi.. CITI_$D# CITI_$D# CITI_$D# CITI_$D#
bonguking Posted July 8, 2011 Author Report Posted July 8, 2011 sorry2 sorry2 gym/lunch elli vachaaa ..thread vadilesaa s%H# s%H#[size=10pt][b]Next Question[/b][/size] [size=12pt][b]You have someone working for you for seven days and you have one gold bar to pay them. The gold bar is segmented into seven connected pieces. You must give them a piece of gold at the end of every day. If you are only allowed to make two breaks in the gold bar, how do you pay your worker?[/b][/size]
Okkamogadu Posted July 8, 2011 Report Posted July 8, 2011 sCo_^Y sCo_^Y sCo_^Y sCo_^Y sCo_^Y[quote author=bonguking link=topic=210373.msg2573973#msg2573973 date=1310148044] sorry2 sorry2 gym/lunch elli vachaaa ..thread vadilesaa s%H# s%H#[size=10pt][b]Next Question[/b][/size] [size=12pt][b]You have someone working for you for seven days and you have one gold bar to pay them. The gold bar is segmented into seven connected pieces. You must give them a piece of gold at the end of every day. If you are only allowed to make two breaks in the gold bar, how do you pay your worker?[/b][/size][/quote]
Okkamogadu Posted July 8, 2011 Report Posted July 8, 2011 CITI#H@ CITI#H@ CITI#H@ CITI#H@ CITI#H@ CITI#H@
Ghajini Posted July 8, 2011 Report Posted July 8, 2011 [quote author=Papachak link=topic=210373.msg2573530#msg2573530 date=1310142155]3 annollu itu randi... Dr@w@ Dr@w@ Dr@w@ Dr@w@4 correct answer... nene correct.... S#d^ S#d^ S#d^ S#d^ S#d^ S#d^[/quote]after a second thought i think the answer is 4assuming the weight of the regular coin is 1unitthe weight of the defective coin will be (1+x) or (1-x)now divide the coins into two parts1.1 part will weigh 6units other part will weigh (6+x) or (6-x)units 2.now take the other part.. this has 6 coins, divide the 6 coins into two groups1 part will weigh 3unitsother part will weigh (3+x) or (3-x)unitsnow take the "other" partit has 3 coins...take any 1 coin and compare the weight with other coins..this requires "2" more stepswhich makes a total of 4 steps #~` #~`
Ghajini Posted July 8, 2011 Report Posted July 8, 2011 [quote author=bonguking link=topic=210373.msg2573973#msg2573973 date=1310148044] sorry2 sorry2 gym/lunch elli vachaaa ..thread vadilesaa s%H# s%H#[size=10pt][b]Next Question[/b][/size] [size=12pt][b]You have someone working for you for seven days and you have one gold bar to pay them. The gold bar is segmented into seven connected pieces. You must give them a piece of gold at the end of every day. If you are only allowed to make two breaks in the gold bar, how do you pay your worker?[/b][/size][/quote] F@!n F@!n F@!n
Ghajini Posted July 8, 2011 Report Posted July 8, 2011 [quote author=Luv Guru link=topic=210373.msg2573449#msg2573449 date=1310140983]150 enti enduku.. sCo_^Y meetadi enti cumulative aaa sCo_^Y Question baagundi.. But ans samaj avvat ledu.. F@!n Microsoft interview question anukuntaaa[/quote][quote author=bonguking link=topic=210373.msg2573458#msg2573458 date=1310141073]emmo baa..evadaikki erukka....naaku question/ and thelusaa esaa anthey ... s%H# s%H#[/quote](1*10 + 2*10 + 3*10 + 4*10 + 5*10)=10(1+2+3+4+5)now lets say if jar "1" is contaminated that means instead of 1*10 you will have 1*9, that makes the total 149150-149=1 s%H# s%H#
Okkamogadu Posted July 8, 2011 Report Posted July 8, 2011 [quote author=Ghajini link=topic=210373.msg2574593#msg2574593 date=1310154258]after a second thought i think the answer is 4assuming the weight of the regular coin is 1unitthe weight of the defective coin will be (1+x) or (1-x)now divide the coins into two parts1.1 part will weigh 6units other part will weigh (6+x) or (6-x)units 2.now take the other part.. this has 6 coins, divide the 6 coins into two groups1 part will weigh 3unitsother part will weigh (3+x) or (3-x)unitsnow take the "other" partit has 3 coins...take any 1 coin and compare the weight with other coins..this requires "2" more stepswhich makes a total of 4 steps #~` #~`[/quote] CITI_$D# CITI_$D# CITI_$D#ghajini baa vochesava.. ee bongu king eedi.. question vesi vellipoyadu..
Ghajini Posted July 8, 2011 Report Posted July 8, 2011 [quote author=EXIT link=topic=210373.msg2574724#msg2574724 date=1310155374] CITI_$D# CITI_$D# CITI_$D#ghajini baa vochesava.. ee bongu king eedi.. question vesi vellipoyadu..[/quote]indaka tinnadi aragataniki gym ki elladu.. ippudu arigipoindi kada ani malli mekkataniki elli untadu CITI_c$y CITI_c$y
bottu_seenu Posted July 8, 2011 Report Posted July 8, 2011 Coins di answer can be 3 12 coins ni 3 groups cheste(4 coins each)step 1) now take group A and group B compare suppose they are equal and faulty coin is in group Cstep 2) Now divide group C into 2-2 coins comapre them againstep 3) now its down to 2 coinscompare the last two you will find the faulty coin.... ee rule ni ye group ki ina apply cheyyochu...... so the answer is 3 #~` #~` #~` #~` #~`
Herndon- VA Posted July 8, 2011 Report Posted July 8, 2011 nice thread nice thread nice thread you rock you rock you rock
Ghajini Posted July 8, 2011 Report Posted July 8, 2011 [quote author=Slim-Shady link=topic=210373.msg2574777#msg2574777 date=1310156003]Coins di answer can be 3 12 coins ni 3 groups cheste(4 coins each)step 1) now take group A and group B compare suppose they are equal and faulty coin is in group Cstep 2) Now divide group C into 2-2 coins comapre them againstep 3) now its down to 2 coinscompare the last two you will find the faulty coin.... ee rule ni ye group ki ina apply cheyyochu...... so the answer is 3 #~` #~` #~` #~` #~`[/quote] CITI_$D# CITI_$D# ee avidia naaku enduku tattaledo F@!n F@!nbtw nee photography etta saagutundi.. sCo_^Y sCo_^Y
rachagadu Posted July 8, 2011 Report Posted July 8, 2011 [quote author=bonguking link=topic=210373.msg2573973#msg2573973 date=1310148044] sorry2 sorry2 gym/lunch elli vachaaa ..thread vadilesaa s%H# s%H#[size=10pt][b]Next Question[/b][/size] [size=12pt][b]You have someone working for you for seven days and you have one gold bar to pay them. The gold bar is segmented into seven connected pieces. You must give them a piece of gold at the end of every day. If you are only allowed to make two breaks in the gold bar, how do you pay your worker?[/b][/size][/quote]take the bar and cut it into 2+5 bars##+#####put the two on top of the one another cut it into two----it should cut the first pice into 2 and the 2nd piece into 1+4 #######then we have#+#+#+####day1---#day2---#day3---#day4----take the 3 back give the 4(####)day5---#day6--#day7--#
Herndon- VA Posted July 8, 2011 Report Posted July 8, 2011 [quote author=Slim-Shady link=topic=210373.msg2574777#msg2574777 date=1310156003]Coins di answer can be 3 12 coins ni 3 groups cheste(4 coins each)step 1) now take group A and group B compare [size=18pt]suppose they are equal and faulty coin is in group C[/size]step 2) Now divide group C into 2-2 coins comapre them againstep 3) now its down to 2 coinscompare the last two you will find the faulty coin.... ee rule ni ye group ki ina apply cheyyochu...... so the answer is 3 #~` #~` #~` #~` #~`[/quote]If the above is not True, no of attempts will become 4.
Ghajini Posted July 8, 2011 Report Posted July 8, 2011 [quote author=rachagadu link=topic=210373.msg2574787#msg2574787 date=1310156174]take the bar and cut it into 2+5 bars##+#####put the two on top of the one another cut it into two----it should cut the first pice into 2 and the 2nd piece into 1+4 #######then we have#+#+#+####day1---#day2---#day3---#day4----take the 3 back give the 4(####)day5---#day6--#day7--#[/quote] :surprised-038: :surprised-038: :surprised-038:
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