k2s Posted September 8, 2011 Author Report Share Posted September 8, 2011 [quote author=John Galt link=topic=234570.msg2924259#msg2924259 date=1315520721]bit level lo anni bits rayalante baaga time pattuddi baa..or lu and le kada..chusi cheseyachu ani cry@fl cry@fl[/quote]u baddakist Quote Link to comment Share on other sites More sharing options...
k2s Posted September 8, 2011 Author Report Share Posted September 8, 2011 [quote author=k2s link=topic=234570.msg2924260#msg2924260 date=1315520762]1 more example: [img]http://www.cisco.com/image/gif/paws/13788/3c.gif[/img] Given the Class C network of 204.15.5.0/24, subnet the network in order to create the network in Figure with the host requirements shown.any one who can solve it for me..... please give full explanation...[/quote]any one working on this ??? Quote Link to comment Share on other sites More sharing options...
ToughGuy Posted September 8, 2011 Report Share Posted September 8, 2011 [quote author=k2s link=topic=234570.msg2924282#msg2924282 date=1315521003]any one working on this ??? [/quote]baa nenu office lo vunna ...lekapothe i would have done it... Quote Link to comment Share on other sites More sharing options...
k2s Posted September 8, 2011 Author Report Share Posted September 8, 2011 [quote author=!!!! FeRRo !!!! link=topic=234570.msg2924303#msg2924303 date=1315521174]baa nenu office lo vunna ...lekapothe i would have done it...[/quote] ^G#Wno baddakism here ....... i want solution that's it Quote Link to comment Share on other sites More sharing options...
k2s Posted September 8, 2011 Author Report Share Posted September 8, 2011 [quote author=k2s link=topic=234570.msg2924260#msg2924260 date=1315520762]1 more example: [img]http://www.cisco.com/image/gif/paws/13788/3c.gif[/img] Given the Class C network of 204.15.5.0/24, subnet the network in order to create the network in Figure with the host requirements shown.any one who can solve it for me..... please give full explanation...[/quote]there could b many solutions to this example. one of the it is : develop a subnetting scheme with the use of VLSM, given: netA: must support 14 hostsnetB: must support 28 hostsnetC: must support 2 hostsnetD: must support 7 hostsnetE: must support 28 hostDetermine what mask allows the required number of hosts. netA: requires a /28 (255.255.255.240) mask to support 14 hostsnetB: requires a /27 (255.255.255.224) mask to support 28 hostsnetC: requires a /30 (255.255.255.252) mask to support 2 hostsnetD*: requires a /28 (255.255.255.240) mask to support 7 hostsnetE: requires a /27 (255.255.255.224) mask to support 28 hosts* a /29 (255.255.255.248) would only allow 6 usable host addresses therefore netD requires a /28 mask.The easiest way to assign the subnets is to assign the largest first. For example, you can assign in this manner: netB: 204.15.5.0/27 host address range 1 to 30netE: 204.15.5.32/27 host address range 33 to 62netA: 204.15.5.64/28 host address range 65 to 78netD: 204.15.5.80/28 host address range 81 to 94netC: 204.15.5.96/30 host address range 97 to 98 Quote Link to comment Share on other sites More sharing options...
krldr871 Posted September 8, 2011 Report Share Posted September 8, 2011 [quote author=k2s link=topic=234570.msg2924260#msg2924260 date=1315520762]1 more example: [img]http://www.cisco.com/image/gif/paws/13788/3c.gif[/img] Given the Class C network of 204.15.5.0/24, subnet the network in order to create the network in Figure with the host requirements shown.any one who can solve it for me..... please give full explanation...[/quote]204.15.5.0 class C..so 24 bits network, 8 host..kani manaki at least 5 subnets kavali..so 27 bits network ki dedicate cheyali..27 network bits tho 8 subnets cheyyachu..each with 30 hosts..204.15.5.0 - 204.15.5.31, 32-63, 64-95 and so on Quote Link to comment Share on other sites More sharing options...
k2s Posted September 8, 2011 Author Report Share Posted September 8, 2011 some more examples : Example: A service provider has given you the Class C network range 209.50.1.0. Your company must break the network into 20 separate subnets. Quote Link to comment Share on other sites More sharing options...
krldr871 Posted September 8, 2011 Report Share Posted September 8, 2011 [quote author=k2s link=topic=234570.msg2924373#msg2924373 date=1315522000]some more examples : Example: A service provider has given you the Class C network range 209.50.1.0. Your company must break the network into 20 separate subnets.[/quote]29 network bits..ante 32 subnets..so each subnet will have 6 hosts each.. &D_@@ &D_@@ &D_@@ &D_@@ Quote Link to comment Share on other sites More sharing options...
k2s Posted September 8, 2011 Author Report Share Posted September 8, 2011 [quote author=k2s link=topic=234570.msg2924373#msg2924373 date=1315522000]some more examples : Example: A service provider has given you the Class C network range 209.50.1.0. Your company must break the network into 20 separate subnets.[/quote]Step 1) Determine the number of subnets and convert to binary- In this example, the binary representation of 20 = 00010100.Step 2) Reserve required bits in subnet mask and find incremental value- The binary value of 20 subnets tells us that we need at least 5 network bits to satisfy this requirement (since you cannot get the number 20 with any less than 5 bits – 10100)- Our original subnet mask is 255.255.255.0 (Class C subnet)- The full binary representation of the subnet mask is as follows:255.255.255.0 = 11111111.11111111.11111111.00000000- We must “convert” 5 of the client bits (0) to network bits (1) in order to satisfy the requirements:New Mask = 11111111.11111111.11111111.11111000- If we convert the mask back to decimal, we now have the subnet mask that will be used on all the new networks – 255.255.255.248- Our increment bit is the last possible network bit, converted back to a binary number:New Mask = 11111111.11111111.11111111.1111(1)000 – bit with the parenthesis is your increment bit. If you convert this bit to a decimal number, it becomes the number „8‟ Step 3) Use increment to find network ranges- Start with your given network address and add your increment to the subnetted octet:209.50.1.0209.50.1.8209.50.1.16…etc- You can now fill in your end ranges, which is the last possible IP address before you start the next range209.50.1.0 – 209.50.1.7209.50.1.8 – 209.50.1.15209.50.1.16 – 209.50.1.23…etc- You can then assign these ranges to your networks! Remember the first and last address from each range (network / broadcast IP) are unusable Quote Link to comment Share on other sites More sharing options...
k2s Posted September 8, 2011 Author Report Share Posted September 8, 2011 Another Example : A service provider has given you the Class C network range 209.50.1.0. Your company must break the network into as many subnets as possible as long as there are at least 50 clients per network. Quote Link to comment Share on other sites More sharing options...
krldr871 Posted September 8, 2011 Report Share Posted September 8, 2011 [quote author=k2s link=topic=234570.msg2924431#msg2924431 date=1315522947]Another Example : A service provider has given you the Class C network range 209.50.1.0. Your company must break the network into as many subnets as possible as long as there are at least 50 clients per network.[/quote]50 clients per network ante 6 hosts bits..so that will make 62 hosts per subnet..4 subnets bhayyaa.. &D_@@ &D_@@ &D_@@ Quote Link to comment Share on other sites More sharing options...
k2s Posted September 8, 2011 Author Report Share Posted September 8, 2011 [quote author=John Galt link=topic=234570.msg2924439#msg2924439 date=1315523048]50 clients per network ante 6 hosts bits..so that will make 62 hosts per subnet..4 subnets bhayyaa.. &D_@@ &D_@@ &D_@@[/quote] sHa_clap4 sHa_clap4 sHa_clap4 Quote Link to comment Share on other sites More sharing options...
k2s Posted September 8, 2011 Author Report Share Posted September 8, 2011 [quote author=k2s link=topic=234570.msg2924431#msg2924431 date=1315522947]Another Example : A service provider has given you the Class C network range 209.50.1.0. Your company must break the network into as many subnets as possible as long as there are at least 50 clients per network.[/quote]Step 1) Determine the number of clients and convert to binary- In this example, the binary representation of 50 = 00110010Step 2) Reserve required bits in subnet mask and find incremental value- The binary value of 50 clients tells us that we need at least 6 client bits to satisfy this requirement (since you cannot get the number 50 with any less than 6 bits – 110010)- Our original subnet mask is 255.255.255.0 (Class C subnet)- The full binary representation of the subnet mask is as follows:255.255.255.0 = 11111111.11111111.11111111.00000000- We must ensure 6 of the client bits (0) remain client bits (save the clients!) in order to satisfy the requirements. All other bits can become network bits:New Mask = 11111111.11111111.11111111.11 000000 note the 6 client bits that we have saved- If we convert the mask back to decimal, we now have the subnet mask that will be used on all the new networks – 255.255.255.192- Our increment bit is the last possible network bit, converted back to a binary number:New Mask = 11111111.11111111.11111111.1(1)000000 – bit with the parenthesis is your increment bit. If you convert this bit to a decimal number, it becomes the number „64‟ Step 3) Use increment to find network ranges- Start with your given network address and add your increment to the subnetted octet:209.50.1.0209.50.1.64209.50.1.128209.50.1.192- You can now fill in your end ranges, which is the last possible IP address before you start the next range209.50.1.0 – 209.50.1.63209.50.1.64 – 209.50.1.127209.50.1.128 – 209.50.1.191209.50.1.192 – 209.50.1.255- You can then assign these ranges to your networks! Remember the first and last address from each range (network / broadcast IP) are unusable Quote Link to comment Share on other sites More sharing options...
k2s Posted September 8, 2011 Author Report Share Posted September 8, 2011 2 Members and 0 Guests are viewing this topic. sFun_duh sFun_duh sFun_duh sFun_duh Quote Link to comment Share on other sites More sharing options...
krldr871 Posted September 8, 2011 Report Share Posted September 8, 2011 [quote author=k2s link=topic=234570.msg2924444#msg2924444 date=1315523144] sHa_clap4 sHa_clap4 sHa_clap4[/quote]nenokkadine sincere student [img]http://i54.tinypic.com/2zhlaon.gif[/img] Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.