quiz questions

[SeemaLekka]

1 minute ago, Spartan said:

where will u be after two years ante..

2020 lo ekkada untavo cheptava..2021 address cheptava.? 

2 years ante 2020 ega nuvvendi factorial esava

[Spartan]

Just now, SeemaLekka said:

2 years ante 2020 ega nuvvendi factorial esava

i read the qn wrong i think. 

[SeemaLekka]

Just now, Spartan said:

i read the qn wrong i think. 

hmm...

[Ara_Tenkai]

9 minutes ago, Spartan said:

expecting two answers.? 2yrs ki 40K and 3yrs ki 88K  

present year population = 2,00,000

after 1 year = 2lakhs*0.2=240K

after 2 years = 240K*0.2=288K

after 3 years = 288K*0.2=345600

345600-288000= 57600

 

[Spartan]

Just now, Ara_Tenkai said:

present year population = 2,00,000

after 1 year = 2lakhs*0.2=240K

after 2 years = 240K*0.2=288K

after 3 years = 288K*0.2=345600

345600-288000= 57600

 

uncle math was right, its about the sentencing. 

[Ara_Tenkai]

Just now, Spartan said:

uncle math was right, its about the sentencing. 

oh ok

[tennisluvr]

On 6/1/2018 at 3:21 PM, chittimallu2 said:

vadu upsc topper ayyada leka cinema lo kullu jokulu raase ulfa writer ayyada... 

Vaade ee taram Kona Venkat nayana

[SonaParv_522]

 Population  of  a  city  decreases  by  10%  at  the  end  of  first  year  and  increases  by   10%  at  the  end  of  second  year  and  again  decreases  by  10%  at  the  end  of  third  year.  If  the  population  of  the  city  at  the  end  of  third  year  is  4455,  then  what  was  the  population  of  the  city  at  the  beginning  of  the  first  year?

[tennisluvr]

7 minutes ago, SonaParv_522 said:

 Population  of  a  city  decreases  by  10%  at  the  end  of  first  year  and  increases  by   10%  at  the  end  of  second  year  and  again  decreases  by  10%  at  the  end  of  third  year.  If  the  population  of  the  city  at  the  end  of  third  year  is  4455,  then  what  was  the  population  of  the  city  at  the  beginning  of  the  first  year?

5000

[SonaParv_522]

10 minutes ago, tennisluvr said:

5000

sorrry you might be right....I havent calculated accurate.

for me I got 4950

I did it like -10+10-10 would be -10 which is wrong

[tennisluvr]

7 minutes ago, SonaParv_522 said:

wrong answer!!!

How? 

M. F  =  90/100*110*100*90/100 =  81*11/1000

Population  before 3Yrs=I.Q /M. F=4455*1000/81*11 = 5000

[k2s]

18 minutes ago, SonaParv_522 said:

 Population  of  a  city  decreases  by  10%  at  the  end  of  first  year  and  increases  by   10%  at  the  end  of  second  year  and  again  decreases  by  10%  at  the  end  of  third  year.  If  the  population  of  the  city  at  the  end  of  third  year  is  4455,  then  what  was  the  population  of  the  city  at  the  beginning  of  the  first  year?

Population now = x

after 1 year = 0.9x

after 2 yrs = (0.9x + 0.1(0.9x)) = 0.9x + 0.09x = 0.99x 

after 3 yrs = 0.99x - 0.1(0.99x) = 0.99x -0.099x = 0.891x

4455 = 0.891x => x = 5000

 

[k2s]

15 minutes ago, tennisluvr said:

5000

10 minutes ago, SonaParv_522 said:

sorrry you might be right....I havent calculated accurate.

Just now, k2s said:

Population now = x

after 1 year = 0.9x

after 2 yrs = (0.9x + 0.1(0.9x)) = 0.9x + 0.09x = 0.99x 

after 3 yrs = 0.99x - 0.1(0.99x) = 0.99x -0.099x = 0.891x

4455 = 0.891x => x = 5000

 

 

[SonaParv_522]

2 minutes ago, k2s said:

 

[k2s]

A and B start swimming simultaneously from opposite ends i.e Deep end & shallow end of a swimming pool with speeds 5m/s and 2 m/s.. They swim and after reaching opposite ends , they change the directions and continue swimming with their respective uniform speeds..when they meet for the 8th time , they meet at a distance of 10meters from the shallow end.

Q) Find the length of the swimming pool.